Aikace-aikacen ATSE-Automatic canja wurin sauyawa zai iya magance matsalar da ke tattare da layi na tsaka tsaki

Canja wurin canja wuri ta atomatik (ATSE)zai iya magance matsalar rikice-rikice na layin tsaka tsaki.To me muke nufi da tsaka tsakin layi?

Hoto 1: ɗauka cewa ƙarfin lantarki naDC ikonwadata shine 220V, kuma ƙimar juriya na masu tsayayyar lodi uku R shine 10 Ohms.Bari mu ƙididdige ƙarfin lantarki a kan mai ɗaukar nauyi Ra:

Ga resistor Ra, muna da:

Lura cewa akwai igiyoyin ruwa guda uku da ke gudana ta hanyar juriya Ra, ɗaya daga cikinsu yana fitowatushen wutan lantarkiEa kuma ya dawo zuwa madaidaicin sandar wutar lantarki ta hanyar LINE N. Sauran fita biyu daga Ea kuma komawa zuwa tashar mara kyau ta hanyar Eb ko Ec.Amma saboda ƙarfin wutar lantarki na maɓuɓɓuka biyu a cikin wannan madauki daidai suke kuma akasin haka, na yanzu ba shi da sifili.
Wani abu da ke buƙatar kulawa ta musamman shine cewa ƙarfin lantarki a wurin N shine 0V.
Bari mu sake duba adadi na 2: N a cikin adadi ya kasu kashi biyu, N da N'.Menene ƙarfin lantarki a fadin resistor Ra?Yana da sauƙi a faɗi cewa ƙarfin lantarki a fadin Ra shine 0V.
Tabbas, abin da ake ji a nan shi ne: sigogin samar da wutar lantarki guda uku da ke cikin da’irar sun yi daidai da juna, haka nan ma’aunin juriya sun yi daidai, har ma da ma’aunin waya, wato juriya na layin, su ma sun yi daidai da juna.
A cikin layi na ainihi, waɗannan sigogi ba za su kasance daidai ba, don haka Ra zai sami ƙananan ƙarfin lantarki.Bari mu kira shi N' ƙarfin lantarki.

Bari mu kalli hoton da ke ƙasa:

Kamar yadda muke iya gani, wutar lantarki a FIG.3 da 4, FIG.1 da FIG.2 ana canza shi daga DC zuwa AC mai kashi uku, kuma ƙarfin lokaci shine 220V, don haka wutar lantarki ta dabi'a ce 380V, kuma bambancin lokaci tsakanin matakan uku shine digiri 120.
Menene ƙarfin lantarki a fadin resistor Ra a hoto na 3?
Tunda manufar wannan post ɗin shine kawai don kwatanta matsalar, ba don yin ƙididdige ƙididdiga na da'ira ba.Ba za mu yi ainihin lissafin ba.
Amma tabbas zamu iya sanin hakan, don FIG.3, ƙarfin lantarki a fadin resistor Ra shima kusan daidai yake da 217.8V kuma ƙarfin tsaka-tsakin sifili ne.
A cikin FIG.4, mun ga cewa n-line ya shiga cikin N da N', to me zai faru da wutar lantarki a wurin N'?
Amsar ita ce daidai ga DC.Idan da'irar ta kasance cikakke daidai, Un 'daidai 0V;Idan ma'aunin kewayawa ba su da daidaituwa, Un 'ba ya kai 0V.
A cikin da'irar aiki, musamman a cikin da'irar haske, AC mai hawa uku yana da asymmetric, don haka halin yanzu yana gudana ta layin N ko layin PEN (layin sifili).Da zarar layin N ko layin PEN ya karye, wutar lantarkin da ke bayan wurin karya yana tashi.A cikin matsanancin yanayi, yana hawa zuwa ƙarfin ƙarfin lokaci, wanda shine 220V.

Mu dubaATSE:

Duba ƙasa:

A cikin wannan hoton muna ganin layin mai shigowa biyu, daATSE, kuma ba shakka nauyin nauyi.Anan, duk da haka, adadin fitilun akan matakai uku sun bambanta, tare da lokaci A shine mafi kayatarwa.
Bari mu yi tunanin hakaATSEyanzu yana rufe madauki T1 a hagu, kuma aikin na yanzu yana tafiya daga T1 zuwa T2.
Idan, a lokacin jujjuyawar, an yanke layin 1N da farko kuma an yanke kashi uku daga baya, to yayin jujjuyawar, za mu iya sani nan da nan daga ilimin da ke sama cewa wutar lantarki na tsaka-tsakin layin na iya tashi ko faduwa.Idan wutar lantarki a kan fitilar ta zarce ƙarfin ƙarfin lokaci da yawa, fitilar za ta ƙone yayin aikin juyawa.
A nan ne madogaran layukan tsaka tsaki ke shigowa.

Menene mafita?

ATSEtare da aikin haɗin layi na tsaka tsaki, lokacin da aka kunna shi, da farko tabbatar da cewa an kunna wutar lantarki mai matakai uku da farko, sannan a kunna layin N a ƙarshe;Lokacin da aka kunna, da farko tabbatar da kunna layin N, sannan kunna wutar lantarki mai nau'i uku.Ko da, ATSE na iya mamaye layin N na hanyoyin biyu nan take.Wannan shine aikin haɗin layin tsaka tsaki.